(2y^2+5)+(y^2-5)=

Solution for (2y^2+5)+(y^2-5)= equation:

Simplifying
(2y2 + 5) + (y2 + -5) = 0

Reorder the terms:
(5 + 2y2) + (y2 + -5) = 0

Remove parenthesis around (5 + 2y2)
5 + 2y2 + (y2 + -5) = 0

Reorder the terms:
5 + 2y2 + (-5 + y2) = 0

Remove parenthesis around (-5 + y2)
5 + 2y2 + -5 + y2 = 0

Reorder the terms:
5 + -5 + 2y2 + y2 = 0

Combine like terms: 5 + -5 = 0
0 + 2y2 + y2 = 0
2y2 + y2 = 0

Combine like terms: 2y2 + y2 = 3y2
3y2 = 0

Solving
3y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '3'.
y2 = 0

Simplifying
y2 = 0

Take the square root of each side:
y = {0}